Solve sqrt{x}+3x=2x

$$\sqrt { x } + 3 x = 2 x$$

Solve for x

$$x=0$$

Solution Steps

Subtract 3x from both sides of the equation.

$$\sqrt{x}=2x-3x$$

Combine 2x and -3x to get -x.

$$\sqrt{x}=-x$$

Square both sides of the equation.

$$\left(\sqrt{x}\right)^{2}=\left(-x\right)^{2}$$

Calculate \sqrt{x} to the power of 2 and get x.

$$x=\left(-x\right)^{2}$$

Expand \left(-x\right)^{2}.

$$x=\left(-1\right)^{2}x^{2}$$

Calculate -1 to the power of 2 and get 1.

$$x=1x^{2}$$

Reorder the terms.

$$x=x^{2}$$

Subtract x^{2} from both sides.

$$x-x^{2}=0$$

Factor out x.

$$x\left(1-x\right)=0$$

To find equation solutions, solve x=0 and 1-x=0.

$$x=0 x=1$$

Substitute 0 for x in the equation \sqrt{x}+3x=2x.

$$\sqrt{0}+3\times 0=2\times 0$$

Simplify. The value x=0 satisfies the equation.

$$0=0$$

Substitute 1 for x in the equation \sqrt{x}+3x=2x.

$$\sqrt{1}+3\times 1=2\times 1$$

Simplify. The value x=1 does not satisfy the equation.

$$4=2$$

Equation \sqrt{x}=-x has a unique solution.

$$x=0$$