Solve sqrt{9}*2^3-3^2*1^3+7*0=

$$\sqrt { 9 } \times 2 ^ { 3 } - 3 ^ { 2 } \times 1 ^ { 3 } + 7 \times 0 =$$

Evaluate

$$15$$

Solution Steps

Calculate the square root of 9 and get 3.

$$3\times 2^{3}-3^{2}\times 1^{3}+7\times 0$$

Calculate 2 to the power of 3 and get 8.

$$3\times 8-3^{2}\times 1^{3}+7\times 0$$

Multiply 3 and 8 to get 24.

$$24-3^{2}\times 1^{3}+7\times 0$$

Calculate 3 to the power of 2 and get 9.

$$24-9\times 1^{3}+7\times 0$$

Calculate 1 to the power of 3 and get 1.

$$24-9\times 1+7\times 0$$

Multiply 9 and 1 to get 9.

$$24-9+7\times 0$$

Subtract 9 from 24 to get 15.

$$15+7\times 0$$

Multiply 7 and 0 to get 0.

$$15+0$$

Add 15 and 0 to get 15.

$$15$$

Factor

$$3\times 5$$