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Differentiate w.r.t. x
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\sqrt{8}x\times 2+\sqrt{3}
Divide \sqrt{8}x by \frac{1}{2} by multiplying \sqrt{8}x by the reciprocal of \frac{1}{2}.
2\sqrt{2}x\times 2+\sqrt{3}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
4\sqrt{2}x+\sqrt{3}
Multiply 2 and 2 to get 4.