Solve sqrt{8}=2sqrt{2}

$$\sqrt { 8 } = 2 \sqrt { 2 }$$

Verify

Solution Steps

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$2\sqrt{2}=2\sqrt{2}$$

Subtract 2\sqrt{2} from both sides.

$$2\sqrt{2}-2\sqrt{2}=0$$

Combine 2\sqrt{2} and -2\sqrt{2} to get 0.

$$0=0$$

Compare 0 and 0.

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