Solve sqrt{6x+33}-13=-10

$$\sqrt { 6 x + 33 } - 13 = - 10$$

Solve for x

$$x=-4$$

Steps for Solving Radical Equations

Add 13 to both sides of the equation.

$$\sqrt{6x+33}-13-\left(-13\right)=-10-\left(-13\right)$$

Subtracting -13 from itself leaves 0.

$$\sqrt{6x+33}=-10-\left(-13\right)$$

Subtract -13 from -10.

$$\sqrt{6x+33}=3$$

Square both sides of the equation.

$$6x+33=9$$

Subtract 33 from both sides of the equation.

$$6x+33-33=9-33$$

Subtracting 33 from itself leaves 0.

$$6x=9-33$$

Subtract 33 from 9.

$$6x=-24$$

Divide both sides by 6.

$$\frac{6x}{6}=-\frac{24}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=-\frac{24}{6}$$

Divide -24 by 6.

$$x=-4$$