Solve for x
x=2
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\left(\sqrt{5x-3}\right)^{2}=\left(\sqrt{2x+3}\right)^{2}
Square both sides of the equation.
5x-3=\left(\sqrt{2x+3}\right)^{2}
Calculate \sqrt{5x-3} to the power of 2 and get 5x-3.
5x-3=2x+3
Calculate \sqrt{2x+3} to the power of 2 and get 2x+3.
5x-3-2x=3
Subtract 2x from both sides.
3x-3=3
Combine 5x and -2x to get 3x.
3x=3+3
Add 3 to both sides.
3x=6
Add 3 and 3 to get 6.
x=\frac{6}{3}
Divide both sides by 3.
x=2
Divide 6 by 3 to get 2.
\sqrt{5\times 2-3}=\sqrt{2\times 2+3}
Substitute 2 for x in the equation \sqrt{5x-3}=\sqrt{2x+3}.
7^{\frac{1}{2}}=7^{\frac{1}{2}}
Simplify. The value x=2 satisfies the equation.
x=2
Equation \sqrt{5x-3}=\sqrt{2x+3} has a unique solution.
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