Solve for x
x=8
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\left(\sqrt{5x+9}\right)^{2}=\left(x-1\right)^{2}
Square both sides of the equation.
5x+9=\left(x-1\right)^{2}
Calculate \sqrt{5x+9} to the power of 2 and get 5x+9.
5x+9=x^{2}-2x+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
5x+9-x^{2}=-2x+1
Subtract x^{2} from both sides.
5x+9-x^{2}+2x=1
Add 2x to both sides.
7x+9-x^{2}=1
Combine 5x and 2x to get 7x.
7x+9-x^{2}-1=0
Subtract 1 from both sides.
7x+8-x^{2}=0
Subtract 1 from 9 to get 8.
-x^{2}+7x+8=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=7 ab=-8=-8
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx+8. To find a and b, set up a system to be solved.
-1,8 -2,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -8.
-1+8=7 -2+4=2
Calculate the sum for each pair.
a=8 b=-1
The solution is the pair that gives sum 7.
\left(-x^{2}+8x\right)+\left(-x+8\right)
Rewrite -x^{2}+7x+8 as \left(-x^{2}+8x\right)+\left(-x+8\right).
-x\left(x-8\right)-\left(x-8\right)
Factor out -x in the first and -1 in the second group.
\left(x-8\right)\left(-x-1\right)
Factor out common term x-8 by using distributive property.
x=8 x=-1
To find equation solutions, solve x-8=0 and -x-1=0.
\sqrt{5\times 8+9}=8-1
Substitute 8 for x in the equation \sqrt{5x+9}=x-1.
7=7
Simplify. The value x=8 satisfies the equation.
\sqrt{5\left(-1\right)+9}=-1-1
Substitute -1 for x in the equation \sqrt{5x+9}=x-1.
2=-2
Simplify. The value x=-1 does not satisfy the equation because the left and the right hand side have opposite signs.
x=8
Equation \sqrt{5x+9}=x-1 has a unique solution.
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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