Solve for n
n=8
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\left(\sqrt{5n+9}\right)^{2}=\left(n-1\right)^{2}
Square both sides of the equation.
5n+9=\left(n-1\right)^{2}
Calculate \sqrt{5n+9} to the power of 2 and get 5n+9.
5n+9=n^{2}-2n+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(n-1\right)^{2}.
5n+9-n^{2}=-2n+1
Subtract n^{2} from both sides.
5n+9-n^{2}+2n=1
Add 2n to both sides.
7n+9-n^{2}=1
Combine 5n and 2n to get 7n.
7n+9-n^{2}-1=0
Subtract 1 from both sides.
7n+8-n^{2}=0
Subtract 1 from 9 to get 8.
-n^{2}+7n+8=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=7 ab=-8=-8
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -n^{2}+an+bn+8. To find a and b, set up a system to be solved.
-1,8 -2,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -8.
-1+8=7 -2+4=2
Calculate the sum for each pair.
a=8 b=-1
The solution is the pair that gives sum 7.
\left(-n^{2}+8n\right)+\left(-n+8\right)
Rewrite -n^{2}+7n+8 as \left(-n^{2}+8n\right)+\left(-n+8\right).
-n\left(n-8\right)-\left(n-8\right)
Factor out -n in the first and -1 in the second group.
\left(n-8\right)\left(-n-1\right)
Factor out common term n-8 by using distributive property.
n=8 n=-1
To find equation solutions, solve n-8=0 and -n-1=0.
\sqrt{5\times 8+9}=8-1
Substitute 8 for n in the equation \sqrt{5n+9}=n-1.
7=7
Simplify. The value n=8 satisfies the equation.
\sqrt{5\left(-1\right)+9}=-1-1
Substitute -1 for n in the equation \sqrt{5n+9}=n-1.
2=-2
Simplify. The value n=-1 does not satisfy the equation because the left and the right hand side have opposite signs.
n=8
Equation \sqrt{5n+9}=n-1 has a unique solution.
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Limits
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