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\sqrt{49+39y}=11+y
Subtract -y from both sides of the equation.
\left(\sqrt{49+39y}\right)^{2}=\left(11+y\right)^{2}
Square both sides of the equation.
49+39y=\left(11+y\right)^{2}
Calculate \sqrt{49+39y} to the power of 2 and get 49+39y.
49+39y=121+22y+y^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(11+y\right)^{2}.
49+39y-121=22y+y^{2}
Subtract 121 from both sides.
-72+39y=22y+y^{2}
Subtract 121 from 49 to get -72.
-72+39y-22y=y^{2}
Subtract 22y from both sides.
-72+17y=y^{2}
Combine 39y and -22y to get 17y.
-72+17y-y^{2}=0
Subtract y^{2} from both sides.
-y^{2}+17y-72=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=17 ab=-\left(-72\right)=72
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -y^{2}+ay+by-72. To find a and b, set up a system to be solved.
1,72 2,36 3,24 4,18 6,12 8,9
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 72.
1+72=73 2+36=38 3+24=27 4+18=22 6+12=18 8+9=17
Calculate the sum for each pair.
a=9 b=8
The solution is the pair that gives sum 17.
\left(-y^{2}+9y\right)+\left(8y-72\right)
Rewrite -y^{2}+17y-72 as \left(-y^{2}+9y\right)+\left(8y-72\right).
-y\left(y-9\right)+8\left(y-9\right)
Factor out -y in the first and 8 in the second group.
\left(y-9\right)\left(-y+8\right)
Factor out common term y-9 by using distributive property.
y=9 y=8
To find equation solutions, solve y-9=0 and -y+8=0.
\sqrt{49+39\times 9}-9=11
Substitute 9 for y in the equation \sqrt{49+39y}-y=11.
11=11
Simplify. The value y=9 satisfies the equation.
\sqrt{49+39\times 8}-8=11
Substitute 8 for y in the equation \sqrt{49+39y}-y=11.
11=11
Simplify. The value y=8 satisfies the equation.
y=9 y=8
List all solutions of \sqrt{39y+49}=y+11.