Solve sqrt{4^2-3^2}+sqrt{3^2-4^2}

$$\sqrt { 4 ^ { 2 } - 3 ^ { 2 } } + \sqrt { 3 ^ { 2 } - 4 ^ { 2 } }$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\sqrt{16-3^{2}}+\sqrt{3^{2}-4^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{16-9}+\sqrt{3^{2}-4^{2}}$$

Subtract 9 from 16 to get 7.

$$\sqrt{7}+\sqrt{3^{2}-4^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{7}+\sqrt{9-4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{7}+\sqrt{9-16}$$

Subtract 16 from 9 to get -7.

$$\sqrt{7}+\sqrt{-7}$$