Solve sqrt{3y+16}+1=3

$$\sqrt { 3 y + 16 } + 1 = 3$$

Solve for y

$$y=-4$$

Steps for Solving Radical Equations

Subtract 1 from both sides of the equation.

$$\sqrt{3y+16}+1-1=3-1$$

Subtracting 1 from itself leaves 0.

$$\sqrt{3y+16}=3-1$$

Subtract 1 from 3.

$$\sqrt{3y+16}=2$$

Square both sides of the equation.

$$3y+16=4$$

Subtract 16 from both sides of the equation.

$$3y+16-16=4-16$$

Subtracting 16 from itself leaves 0.

$$3y=4-16$$

Subtract 16 from 4.

$$3y=-12$$

Divide both sides by 3.

$$\frac{3y}{3}=-\frac{12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=-\frac{12}{3}$$

Divide -12 by 3.

$$y=-4$$