Solve for x
x=\frac{\sqrt{3}\left(±8+y\right)}{3}
Solve for y
y=-\left(±8\right)+\sqrt{3}x
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\sqrt{3}x=±8+y
Add y to both sides.
\frac{\sqrt{3}x}{\sqrt{3}}=\frac{±8+y}{\sqrt{3}}
Divide both sides by \sqrt{3}.
x=\frac{±8+y}{\sqrt{3}}
Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.
x=\frac{\sqrt{3}\left(±8+y\right)}{3}
Divide ±8+y by \sqrt{3}.
-y=±8-\sqrt{3}x
Subtract \sqrt{3}x from both sides.
\frac{-y}{-1}=\frac{±8-\sqrt{3}x}{-1}
Divide both sides by -1.
y=\frac{±8-\sqrt{3}x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=-\left(±8\right)+\sqrt{3}x
Divide ±8-\sqrt{3}x by -1.
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