Solve for g
g=\frac{\sqrt{3}}{3x}
x\neq 0
Solve for x
x=\frac{\sqrt{3}}{3g}
g\neq 0
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\sqrt{3}xg=1
The equation is in standard form.
\frac{\sqrt{3}xg}{\sqrt{3}x}=\frac{1}{\sqrt{3}x}
Divide both sides by \sqrt{3}x.
g=\frac{1}{\sqrt{3}x}
Dividing by \sqrt{3}x undoes the multiplication by \sqrt{3}x.
g=\frac{\sqrt{3}}{3x}
Divide 1 by \sqrt{3}x.
\sqrt{3}gx=1
The equation is in standard form.
\frac{\sqrt{3}gx}{\sqrt{3}g}=\frac{1}{\sqrt{3}g}
Divide both sides by \sqrt{3}g.
x=\frac{1}{\sqrt{3}g}
Dividing by \sqrt{3}g undoes the multiplication by \sqrt{3}g.
x=\frac{\sqrt{3}}{3g}
Divide 1 by \sqrt{3}g.
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