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\sqrt{3}-\frac{\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{1}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\sqrt{3}-\frac{\sqrt{3}}{3}
The square of \sqrt{3} is 3.
\frac{2}{3}\sqrt{3}
Combine \sqrt{3} and -\frac{\sqrt{3}}{3} to get \frac{2}{3}\sqrt{3}.