Solve sqrt{3}(x+1)=x-1

$$\sqrt { 3 } ( x + 1 ) = x - 1$$

Solve for x

$$x=-\sqrt{3}-2\approx -3.732050808$$

Steps for Solving Linear Equation

Use the distributive property to multiply \sqrt{3} by x+1.

$$\sqrt{3}x+\sqrt{3}=x-1$$

Subtract x from both sides.

$$\sqrt{3}x+\sqrt{3}-x=-1$$

Subtract \sqrt{3} from both sides.

$$\sqrt{3}x-x=-1-\sqrt{3}$$

Combine all terms containing x.

$$\left(\sqrt{3}-1\right)x=-1-\sqrt{3}$$

The equation is in standard form.

$$\left(\sqrt{3}-1\right)x=-\sqrt{3}-1$$

Divide both sides by \sqrt{3}-1.

$$\frac{\left(\sqrt{3}-1\right)x}{\sqrt{3}-1}=\frac{-\sqrt{3}-1}{\sqrt{3}-1}$$

Dividing by \sqrt{3}-1 undoes the multiplication by \sqrt{3}-1.

$$x=\frac{-\sqrt{3}-1}{\sqrt{3}-1}$$

Divide -1-\sqrt{3} by \sqrt{3}-1.

$$x=-\sqrt{3}-2$$