Solve sqrt3^2-(sqrt{3}div2)^2=

$$\sqrt { 3 } ^ { 2 } - ( \sqrt { 3 } \div 2 ) ^ { 2 } =$$

Evaluate

$$\frac{9}{4}=2.25$$

Solution Steps

The square of \sqrt{3} is 3.

$$3-\left(\frac{\sqrt{3}}{2}\right)^{2}$$

To raise \frac{\sqrt{3}}{2} to a power, raise both numerator and denominator to the power and then divide.

$$3-\frac{\left(\sqrt{3}\right)^{2}}{2^{2}}$$

The square of \sqrt{3} is 3.

$$3-\frac{3}{2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$3-\frac{3}{4}$$

Subtract \frac{3}{4} from 3 to get \frac{9}{4}.

$$\frac{9}{4}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {2}} = 2\frac{1}{4} = 2.25$$