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\sqrt{3}+2+\sqrt{5}+\sqrt{6}+\sqrt{7}+\sqrt{8}
Calculate the square root of 4 and get 2.
\sqrt{3}+2+\sqrt{5}+\sqrt{6}+\sqrt{7}+2\sqrt{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.