Solve sqrt{2x-1}=pm6

$$\sqrt { 2 x - 1 } = \pm 6$$

Solve for x

$$x=\frac{\left(±6\right)^{2}+1}{2}$$

$$±6\geq 0$$

Steps for Solving Radical Equations

Square both sides of the equation.

$$2x-1=\left(±6\right)^{2}$$

Add 1 to both sides of the equation.

$$2x-1-\left(-1\right)=\left(±6\right)^{2}-\left(-1\right)$$

Subtracting -1 from itself leaves 0.

$$2x=\left(±6\right)^{2}-\left(-1\right)$$

Subtract -1 from \left(±6\right)^{2}.

$$2x=\left(±6\right)^{2}+1$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\left(±6\right)^{2}+1}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\left(±6\right)^{2}+1}{2}$$

Solve for x (complex solution)

$$x=\frac{\left(±6\right)^{2}+1}{2}$$