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\sqrt{2x+15}=x+6
Subtract -6 from both sides of the equation.
\left(\sqrt{2x+15}\right)^{2}=\left(x+6\right)^{2}
Square both sides of the equation.
2x+15=\left(x+6\right)^{2}
Calculate \sqrt{2x+15} to the power of 2 and get 2x+15.
2x+15=x^{2}+12x+36
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+6\right)^{2}.
2x+15-x^{2}=12x+36
Subtract x^{2} from both sides.
2x+15-x^{2}-12x=36
Subtract 12x from both sides.
-10x+15-x^{2}=36
Combine 2x and -12x to get -10x.
-10x+15-x^{2}-36=0
Subtract 36 from both sides.
-10x-21-x^{2}=0
Subtract 36 from 15 to get -21.
-x^{2}-10x-21=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=-10 ab=-\left(-21\right)=21
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-21. To find a and b, set up a system to be solved.
-1,-21 -3,-7
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 21.
-1-21=-22 -3-7=-10
Calculate the sum for each pair.
a=-3 b=-7
The solution is the pair that gives sum -10.
\left(-x^{2}-3x\right)+\left(-7x-21\right)
Rewrite -x^{2}-10x-21 as \left(-x^{2}-3x\right)+\left(-7x-21\right).
x\left(-x-3\right)+7\left(-x-3\right)
Factor out x in the first and 7 in the second group.
\left(-x-3\right)\left(x+7\right)
Factor out common term -x-3 by using distributive property.
x=-3 x=-7
To find equation solutions, solve -x-3=0 and x+7=0.
\sqrt{2\left(-3\right)+15}-6=-3
Substitute -3 for x in the equation \sqrt{2x+15}-6=x.
-3=-3
Simplify. The value x=-3 satisfies the equation.
\sqrt{2\left(-7\right)+15}-6=-7
Substitute -7 for x in the equation \sqrt{2x+15}-6=x.
-5=-7
Simplify. The value x=-7 does not satisfy the equation.
x=-3
Equation \sqrt{2x+15}=x+6 has a unique solution.