Solve for x
x=4
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\left(\sqrt{2x+15}\right)^{2}=\left(\sqrt{5x+3}\right)^{2}
Square both sides of the equation.
2x+15=\left(\sqrt{5x+3}\right)^{2}
Calculate \sqrt{2x+15} to the power of 2 and get 2x+15.
2x+15=5x+3
Calculate \sqrt{5x+3} to the power of 2 and get 5x+3.
2x+15-5x=3
Subtract 5x from both sides.
-3x+15=3
Combine 2x and -5x to get -3x.
-3x=3-15
Subtract 15 from both sides.
-3x=-12
Subtract 15 from 3 to get -12.
x=\frac{-12}{-3}
Divide both sides by -3.
x=4
Divide -12 by -3 to get 4.
\sqrt{2\times 4+15}=\sqrt{5\times 4+3}
Substitute 4 for x in the equation \sqrt{2x+15}=\sqrt{5x+3}.
23^{\frac{1}{2}}=23^{\frac{1}{2}}
Simplify. The value x=4 satisfies the equation.
x=4
Equation \sqrt{2x+15}=\sqrt{5x+3} has a unique solution.
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