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factor(\sqrt{2ab}+\frac{\frac{2}{3}a^{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}})
Rationalize the denominator of \frac{\frac{2}{3}a^{2}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
factor(\sqrt{2ab}+\frac{\frac{2}{3}a^{2}\sqrt{3}}{3})
The square of \sqrt{3} is 3.
factor(\sqrt{2ab}+\frac{2}{9}a^{2}\sqrt{3})
Divide \frac{2}{3}a^{2}\sqrt{3} by 3 to get \frac{2}{9}a^{2}\sqrt{3}.
\frac{9\sqrt{2}\sqrt{ab}+2a^{2}\sqrt{3}}{9}
Factor out \frac{1}{9}.
\sqrt{2}\left(9\sqrt{ab}+\sqrt{2}a^{2}\sqrt{3}\right)
Consider 9\sqrt{2}\sqrt{ab}+2a^{2}\sqrt{3}. Factor out \sqrt{2}.
\frac{\sqrt{2}\left(9\sqrt{ab}+\sqrt{2}a^{2}\sqrt{3}\right)}{9}
Rewrite the complete factored expression.