Solve for a
a=\frac{\left(±3\right)^{2}+1}{2}
±3\geq 0
Solve for a (complex solution)
a=\frac{\left(±3\right)^{2}+1}{2}
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2a-1=\left(±3\right)^{2}
Square both sides of the equation.
2a-1-\left(-1\right)=\left(±3\right)^{2}-\left(-1\right)
Add 1 to both sides of the equation.
2a=\left(±3\right)^{2}-\left(-1\right)
Subtracting -1 from itself leaves 0.
2a=\left(±3\right)^{2}+1
Subtract -1 from \left(±3\right)^{2}.
\frac{2a}{2}=\frac{\left(±3\right)^{2}+1}{2}
Divide both sides by 2.
a=\frac{\left(±3\right)^{2}+1}{2}
Dividing by 2 undoes the multiplication by 2.
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