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Solve for m
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\sqrt{2}m\mu x+3=x
Add x to both sides. Anything plus zero gives itself.
\sqrt{2}m\mu x=x-3
Subtract 3 from both sides.
\sqrt{2}x\mu m=x-3
The equation is in standard form.
\frac{\sqrt{2}x\mu m}{\sqrt{2}x\mu }=\frac{x-3}{\sqrt{2}x\mu }
Divide both sides by \sqrt{2}\mu x.
m=\frac{x-3}{\sqrt{2}x\mu }
Dividing by \sqrt{2}\mu x undoes the multiplication by \sqrt{2}\mu x.
m=\frac{\sqrt{2}\left(x-3\right)}{2x\mu }
Divide x-3 by \sqrt{2}\mu x.
\sqrt{2}m\mu x-x=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
\left(\sqrt{2}m\mu -1\right)x=-3
Combine all terms containing x.
\frac{\left(\sqrt{2}m\mu -1\right)x}{\sqrt{2}m\mu -1}=-\frac{3}{\sqrt{2}m\mu -1}
Divide both sides by \sqrt{2}m\mu -1.
x=-\frac{3}{\sqrt{2}m\mu -1}
Dividing by \sqrt{2}m\mu -1 undoes the multiplication by \sqrt{2}m\mu -1.