Solve sqrt{2}m+2n=7

$$\sqrt { 2 } m + 2 n = 7$$

Solve for m

$$m=-\frac{\sqrt{2}\left(2n-7\right)}{2}$$

Steps for Solving Linear Equation

Subtract 2n from both sides.

$$\sqrt{2}m=7-2n$$

Divide both sides by \sqrt{2}.

$$\frac{\sqrt{2}m}{\sqrt{2}}=\frac{7-2n}{\sqrt{2}}$$

Dividing by \sqrt{2} undoes the multiplication by \sqrt{2}.

$$m=\frac{7-2n}{\sqrt{2}}$$

Divide 7-2n by \sqrt{2}.

$$m=\frac{\sqrt{2}\left(7-2n\right)}{2}$$

Solve for n

$$n=\frac{-\sqrt{2}m+7}{2}$$

Steps for Solving Linear Equation

Subtract \sqrt{2}m from both sides.

$$2n=7-\sqrt{2}m$$

Reorder the terms.

$$2n=-\sqrt{2}m+7$$

Divide both sides by 2.

$$\frac{2n}{2}=\frac{-\sqrt{2}m+7}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$n=\frac{-\sqrt{2}m+7}{2}$$