Solve sqrt{2}-3x=sqrt{3}+2x

$$\sqrt { 2 } - 3 x = \sqrt { 3 } + 2 x$$

Solve for x

$$x=\frac{\sqrt{2}-\sqrt{3}}{5}\approx -0.063567449$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$\sqrt{2}-3x-2x=\sqrt{3}$$

Combine -3x and -2x to get -5x.

$$\sqrt{2}-5x=\sqrt{3}$$

Subtract \sqrt{2} from both sides.

$$-5x=\sqrt{3}-\sqrt{2}$$

Divide both sides by -5.

$$\frac{-5x}{-5}=\frac{\sqrt{3}-\sqrt{2}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$x=\frac{\sqrt{3}-\sqrt{2}}{-5}$$

Divide \sqrt{3}-\sqrt{2} by -5.

$$x=\frac{\sqrt{2}-\sqrt{3}}{5}$$