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\sqrt{2}\left(2\sqrt{2}+\sqrt{2}\right)
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\sqrt{2}\times 3\sqrt{2}
Combine 2\sqrt{2} and \sqrt{2} to get 3\sqrt{2}.
2\times 3
Multiply \sqrt{2} and \sqrt{2} to get 2.
6
Multiply 2 and 3 to get 6.