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\frac{\sqrt{2}}{2\sqrt{3}}-1
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{\sqrt{2}\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}-1
Rationalize the denominator of \frac{\sqrt{2}}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{2}\sqrt{3}}{2\times 3}-1
The square of \sqrt{3} is 3.
\frac{\sqrt{6}}{2\times 3}-1
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
\frac{\sqrt{6}}{6}-1
Multiply 2 and 3 to get 6.
\frac{\sqrt{6}}{6}-\frac{6}{6}
To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{6}{6}.
\frac{\sqrt{6}-6}{6}
Since \frac{\sqrt{6}}{6} and \frac{6}{6} have the same denominator, subtract them by subtracting their numerators.