Solve sqrt{2}*2-m=sqrt{8}

$$\sqrt { 2 } \cdot 2 - m = \sqrt { 8 }$$

Solve for m

$$m=0$$

Steps for Solving Linear Equation

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$2\sqrt{2}-m=2\sqrt{2}$$

Subtract 2\sqrt{2} from both sides.

$$-m=2\sqrt{2}-2\sqrt{2}$$

Combine 2\sqrt{2} and -2\sqrt{2} to get 0.

$$-m=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -1 is not equal to 0, m must be equal to 0.

$$m=0$$