Solve sqrt{2^2-9^2+15}+sqrt{25}-sqrt{36}=

$$\sqrt { 2 ^ { 2 } - 9 ^ { 2 } + 15 } + \sqrt { 25 } - \sqrt { 36 } =$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{4-9^{2}+15}+\sqrt{25}-\sqrt{36}$$

Calculate 9 to the power of 2 and get 81.

$$\sqrt{4-81+15}+\sqrt{25}-\sqrt{36}$$

Subtract 81 from 4 to get -77.

$$\sqrt{-77+15}+\sqrt{25}-\sqrt{36}$$

Add -77 and 15 to get -62.

$$\sqrt{-62}+\sqrt{25}-\sqrt{36}$$

Calculate the square root of 25 and get 5.

$$\sqrt{-62}+5-\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$\sqrt{-62}+5-6$$

Subtract 6 from 5 to get -1.

$$\sqrt{-62}-1$$

Evaluate (complex solution)

$$-1+\sqrt{62}i\approx -1+7.874007874i$$

Real Part (complex solution)

$$-1$$