Solve sqrt{18}+sqrt{72}

$$\sqrt { 18 } + \sqrt { 72 }$$

Evaluate

$$9\sqrt{2}\approx 12.727922061$$

Solution Steps

Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.

$$3\sqrt{2}+\sqrt{72}$$

Factor 72=6^{2}\times 2. Rewrite the square root of the product \sqrt{6^{2}\times 2} as the product of square roots \sqrt{6^{2}}\sqrt{2}. Take the square root of 6^{2}.

$$3\sqrt{2}+6\sqrt{2}$$

Combine 3\sqrt{2} and 6\sqrt{2} to get 9\sqrt{2}.

$$9\sqrt{2}$$