Solve sqrt{16-(2^5-2^4-5^0*3^2)}

$$\sqrt { 16 - ( 2 ^ { 5 } - 2 ^ { 4 } - 5 ^ { 0 } \times 3 ^ { 2 } ) }$$

Evaluate

$$3$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$\sqrt{16-\left(32-2^{4}-5^{0}\times 3^{2}\right)}$$

Calculate 2 to the power of 4 and get 16.

$$\sqrt{16-\left(32-16-5^{0}\times 3^{2}\right)}$$

Subtract 16 from 32 to get 16.

$$\sqrt{16-\left(16-5^{0}\times 3^{2}\right)}$$

Calculate 5 to the power of 0 and get 1.

$$\sqrt{16-\left(16-1\times 3^{2}\right)}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{16-\left(16-1\times 9\right)}$$

Multiply 1 and 9 to get 9.

$$\sqrt{16-\left(16-9\right)}$$

Subtract 9 from 16 to get 7.

$$\sqrt{16-7}$$

Subtract 7 from 16 to get 9.

$$\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$3$$

Factor

$$3$$