Solve sqrt{16}-(-3)^2-sqrt{2^2}

$$\sqrt { 16 } - ( - 3 ) ^ { 2 } - \sqrt { 2 ^ { 2 } }$$

Evaluate

$$-7$$

Solution Steps

Calculate the square root of 16 and get 4.

$$4-\left(-3\right)^{2}-\sqrt{2^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$4-9-\sqrt{2^{2}}$$

Subtract 9 from 4 to get -5.

$$-5-\sqrt{2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$-5-\sqrt{4}$$

Calculate the square root of 4 and get 2.

$$-5-2$$

Subtract 2 from -5 to get -7.

$$-7$$

Factor

$$-7$$