Solve for x
x=8
x=3
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\sqrt{13x-23}=x+1
Subtract -1 from both sides of the equation.
\left(\sqrt{13x-23}\right)^{2}=\left(x+1\right)^{2}
Square both sides of the equation.
13x-23=\left(x+1\right)^{2}
Calculate \sqrt{13x-23} to the power of 2 and get 13x-23.
13x-23=x^{2}+2x+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.
13x-23-x^{2}=2x+1
Subtract x^{2} from both sides.
13x-23-x^{2}-2x=1
Subtract 2x from both sides.
11x-23-x^{2}=1
Combine 13x and -2x to get 11x.
11x-23-x^{2}-1=0
Subtract 1 from both sides.
11x-24-x^{2}=0
Subtract 1 from -23 to get -24.
-x^{2}+11x-24=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=11 ab=-\left(-24\right)=24
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-24. To find a and b, set up a system to be solved.
1,24 2,12 3,8 4,6
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.
1+24=25 2+12=14 3+8=11 4+6=10
Calculate the sum for each pair.
a=8 b=3
The solution is the pair that gives sum 11.
\left(-x^{2}+8x\right)+\left(3x-24\right)
Rewrite -x^{2}+11x-24 as \left(-x^{2}+8x\right)+\left(3x-24\right).
-x\left(x-8\right)+3\left(x-8\right)
Factor out -x in the first and 3 in the second group.
\left(x-8\right)\left(-x+3\right)
Factor out common term x-8 by using distributive property.
x=8 x=3
To find equation solutions, solve x-8=0 and -x+3=0.
\sqrt{13\times 8-23}-1=8
Substitute 8 for x in the equation \sqrt{13x-23}-1=x.
8=8
Simplify. The value x=8 satisfies the equation.
\sqrt{13\times 3-23}-1=3
Substitute 3 for x in the equation \sqrt{13x-23}-1=x.
3=3
Simplify. The value x=3 satisfies the equation.
x=8 x=3
List all solutions of \sqrt{13x-23}=x+1.
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