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\sqrt{48^{2}+\left(2-53\right)^{2}}
Subtract 5 from 53 to get 48.
\sqrt{2304+\left(2-53\right)^{2}}
Calculate 48 to the power of 2 and get 2304.
\sqrt{2304+\left(-51\right)^{2}}
Subtract 53 from 2 to get -51.
\sqrt{2304+2601}
Calculate -51 to the power of 2 and get 2601.
\sqrt{4905}
Add 2304 and 2601 to get 4905.
3\sqrt{545}
Factor 4905=3^{2}\times 545. Rewrite the square root of the product \sqrt{3^{2}\times 545} as the product of square roots \sqrt{3^{2}}\sqrt{545}. Take the square root of 3^{2}.