Solve sqrt{(-2)^6}0,3^4(-4)^2

$$\sqrt { ( - 2 ) ^ { 6 } } 0,3 ^ { 4 } ( - 4 ) ^ { 2 }$$

Evaluate

$$0$$

Solution Steps

Calculate -2 to the power of 6 and get 64.

$$0\sqrt{64}\times 3^{4}\left(-4\right)^{2}$$

Calculate the square root of 64 and get 8.

$$0\times 8\times 3^{4}\left(-4\right)^{2}$$

Multiply 0 and 8 to get 0.

$$0\times 3^{4}\left(-4\right)^{2}$$

Calculate 3 to the power of 4 and get 81.

$$0\times 81\left(-4\right)^{2}$$

Multiply 0 and 81 to get 0.

$$0\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$0\times 16$$

Multiply 0 and 16 to get 0.

$$0$$

Factor

$$0$$