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\sqrt{\frac{7}{12}\times \frac{7}{3}}=x\left(\frac{2}{5}+\frac{1}{8}\right)
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
\sqrt{\frac{7\times 7}{12\times 3}}=x\left(\frac{2}{5}+\frac{1}{8}\right)
Multiply \frac{7}{12} times \frac{7}{3} by multiplying numerator times numerator and denominator times denominator.
\sqrt{\frac{49}{36}}=x\left(\frac{2}{5}+\frac{1}{8}\right)
Do the multiplications in the fraction \frac{7\times 7}{12\times 3}.
\frac{7}{6}=x\left(\frac{2}{5}+\frac{1}{8}\right)
Rewrite the square root of the division \frac{49}{36} as the division of square roots \frac{\sqrt{49}}{\sqrt{36}}. Take the square root of both numerator and denominator.
\frac{7}{6}=x\left(\frac{16}{40}+\frac{5}{40}\right)
Least common multiple of 5 and 8 is 40. Convert \frac{2}{5} and \frac{1}{8} to fractions with denominator 40.
\frac{7}{6}=x\times \frac{16+5}{40}
Since \frac{16}{40} and \frac{5}{40} have the same denominator, add them by adding their numerators.
\frac{7}{6}=x\times \frac{21}{40}
Add 16 and 5 to get 21.
x\times \frac{21}{40}=\frac{7}{6}
Swap sides so that all variable terms are on the left hand side.
x=\frac{7}{6}\times \frac{40}{21}
Multiply both sides by \frac{40}{21}, the reciprocal of \frac{21}{40}.
x=\frac{7\times 40}{6\times 21}
Multiply \frac{7}{6} times \frac{40}{21} by multiplying numerator times numerator and denominator times denominator.
x=\frac{280}{126}
Do the multiplications in the fraction \frac{7\times 40}{6\times 21}.
x=\frac{20}{9}
Reduce the fraction \frac{280}{126} to lowest terms by extracting and canceling out 14.