Solve sqrt{4/9+7/12-1/36}:(1-2/3)+0,1^-2=

$$\sqrt { \frac { 4 } { 9 } + \frac { 7 } { 12 } - \frac { 1 } { 36 } } : ( 1 - \frac { 2 } { 3 } ) + 0,1 ^ { - 2 } =$$

Evaluate

$$3$$

Solution Steps

Add \frac{4}{9} and \frac{7}{12} to get \frac{37}{36}.

$$\frac{\sqrt{\frac{37}{36}-\frac{1}{36}}}{1-\frac{2}{3}}+0\times 1^{-2}$$

Subtract \frac{1}{36} from \frac{37}{36} to get 1.

$$\frac{\sqrt{1}}{1-\frac{2}{3}}+0\times 1^{-2}$$

Calculate the square root of 1 and get 1.

$$\frac{1}{1-\frac{2}{3}}+0\times 1^{-2}$$

Subtract \frac{2}{3} from 1 to get \frac{1}{3}.

$$\frac{1}{\frac{1}{3}}+0\times 1^{-2}$$

Divide 1 by \frac{1}{3} by multiplying 1 by the reciprocal of \frac{1}{3}.

$$1\times 3+0\times 1^{-2}$$

Multiply 1 and 3 to get 3.

$$3+0\times 1^{-2}$$

Calculate 1 to the power of -2 and get 1.

$$3+0\times 1$$

Multiply 0 and 1 to get 0.

$$3+0$$

Add 3 and 0 to get 3.

$$3$$

Factor

$$3$$