Solve sqrt{{10+4*(3-2)-2*[10-2*(4-2)]}*3}

$$\sqrt { \{ 10 + 4 \cdot ( 3 - 2 ) - 2 \cdot [ 10 - 2 \cdot ( 4 - 2 ) ] \} \cdot 3 }$$

Evaluate

$$\sqrt{6}\approx 2.449489743$$

Solution Steps

Subtract 2 from 3 to get 1.

$$\sqrt{\left(10+4\times 1-2\left(10-2\left(4-2\right)\right)\right)\times 3}$$

Multiply 4 and 1 to get 4.

$$\sqrt{\left(10+4-2\left(10-2\left(4-2\right)\right)\right)\times 3}$$

Add 10 and 4 to get 14.

$$\sqrt{\left(14-2\left(10-2\left(4-2\right)\right)\right)\times 3}$$

Subtract 2 from 4 to get 2.

$$\sqrt{\left(14-2\left(10-2\times 2\right)\right)\times 3}$$

Multiply 2 and 2 to get 4.

$$\sqrt{\left(14-2\left(10-4\right)\right)\times 3}$$

Subtract 4 from 10 to get 6.

$$\sqrt{\left(14-2\times 6\right)\times 3}$$

Multiply 2 and 6 to get 12.

$$\sqrt{\left(14-12\right)\times 3}$$

Subtract 12 from 14 to get 2.

$$\sqrt{2\times 3}$$

Multiply 2 and 3 to get 6.

$$\sqrt{6}$$