Solve for b
b=\frac{5x}{2}+1
Solve for x
x=\frac{2\left(b-1\right)}{5}
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b=\frac{5}{2}x+3-2
Divide each term of 5x+6 by 2 to get \frac{5}{2}x+3.
b=\frac{5}{2}x+1
Subtract 2 from 3 to get 1.
b=\frac{5}{2}x+3-2
Divide each term of 5x+6 by 2 to get \frac{5}{2}x+3.
b=\frac{5}{2}x+1
Subtract 2 from 3 to get 1.
\frac{5}{2}x+1=b
Swap sides so that all variable terms are on the left hand side.
\frac{5}{2}x=b-1
Subtract 1 from both sides.
\frac{\frac{5}{2}x}{\frac{5}{2}}=\frac{b-1}{\frac{5}{2}}
Divide both sides of the equation by \frac{5}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{b-1}{\frac{5}{2}}
Dividing by \frac{5}{2} undoes the multiplication by \frac{5}{2}.
x=\frac{2b-2}{5}
Divide b-1 by \frac{5}{2} by multiplying b-1 by the reciprocal of \frac{5}{2}.
Examples
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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