\quad \text { (c) } \frac { x } { 5 } + 4 = 5
Solve for c
c=\frac{5}{x}
x\neq 0
Solve for x
x=\frac{5}{c}
c\neq 0
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cx+20=25
Multiply both sides of the equation by 5.
cx=25-20
Subtract 20 from both sides.
cx=5
Subtract 20 from 25 to get 5.
xc=5
The equation is in standard form.
\frac{xc}{x}=\frac{5}{x}
Divide both sides by x.
c=\frac{5}{x}
Dividing by x undoes the multiplication by x.
cx+20=25
Multiply both sides of the equation by 5.
cx=25-20
Subtract 20 from both sides.
cx=5
Subtract 20 from 25 to get 5.
\frac{cx}{c}=\frac{5}{c}
Divide both sides by c.
x=\frac{5}{c}
Dividing by c undoes the multiplication by c.
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