Solve pigamma^2=4pi

$$\pi \gamma ^ { 2 } = 4 \pi$$

Solve for γ

$$\gamma =2$$

$$\gamma =-2$$

Steps Using Difference of Squares

Cancel out \pi on both sides.

$$\gamma ^{2}=4$$

Subtract 4 from both sides.

$$\gamma ^{2}-4=0$$

Consider \gamma ^{2}-4. Rewrite \gamma ^{2}-4 as \gamma ^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(\gamma -2\right)\left(\gamma +2\right)=0$$

To find equation solutions, solve \gamma -2=0 and \gamma +2=0.

$$\gamma =2 \gamma =-2$$

Steps by Finding Square Root

Cancel out \pi on both sides.

$$\gamma ^{2}=4$$

Take the square root of both sides of the equation.

$$\gamma =2 \gamma =-2$$

Steps Using the Quadratic Formula

Cancel out \pi on both sides.

$$\gamma ^{2}=4$$

Subtract 4 from both sides.

$$\gamma ^{2}-4=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$\gamma =\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Square 0.

$$\gamma =\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Multiply -4 times -4.

$$\gamma =\frac{0±\sqrt{16}}{2}$$

Take the square root of 16.

$$\gamma =\frac{0±4}{2}$$

Now solve the equation \gamma =\frac{0±4}{2} when ± is plus. Divide 4 by 2.

$$\gamma =2$$

Now solve the equation \gamma =\frac{0±4}{2} when ± is minus. Divide -4 by 2.

$$\gamma =-2$$

The equation is now solved.

$$\gamma =2 \gamma =-2$$