Solve pi^0+sqrt{16}+(1/2)^-1-|-4|

$$\pi ^ { 0 } + \sqrt { 16 } + ( \frac { 1 } { 2 } ) ^ { - 1 } - | - 4 |$$

Evaluate

$$3$$

Solution Steps

Calculate \pi to the power of 0 and get 1.

$$1+\sqrt{16}+\left(\frac{1}{2}\right)^{-1}-|-4|$$

Calculate the square root of 16 and get 4.

$$1+4+\left(\frac{1}{2}\right)^{-1}-|-4|$$

Add 1 and 4 to get 5.

$$5+\left(\frac{1}{2}\right)^{-1}-|-4|$$

Calculate \frac{1}{2} to the power of -1 and get 2.

$$5+2-|-4|$$

Add 5 and 2 to get 7.

$$7-|-4|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$7-4$$

Subtract 4 from 7 to get 3.

$$3$$

Factor

$$3$$