Solve pi=x^2+0.1

$$\pi = { x }^{ 2 } +0.1$$

Solve for x (complex solution)

$$x=-\sqrt{\pi -0.1}\approx -1.744016242$$

$$x=\sqrt{\pi -0.1}\approx 1.744016242$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+0.1=\pi$$

Subtract 0.1 from both sides.

$$x^{2}=\pi -0.1$$

The equation is now solved.

$$x=\sqrt{\pi -0.1} x=-\sqrt{\pi -0.1}$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+0.1=\pi$$

Subtract \pi from both sides.

$$x^{2}+0.1-\pi =0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0.1-\pi for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(0.1-\pi \right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(0.1-\pi \right)}}{2}$$

Multiply -4 times 0.1-\pi .

$$x=\frac{0±\sqrt{4\pi -0.4}}{2}$$

Now solve the equation x=\frac{0±\sqrt{4\pi -0.4}}{2} when ± is plus.

$$x=\frac{\sqrt{4\pi -0.4}}{2}$$

Now solve the equation x=\frac{0±\sqrt{4\pi -0.4}}{2} when ± is minus.

$$x=-\frac{\sqrt{4\pi -0.4}}{2}$$

The equation is now solved.

$$x=\frac{\sqrt{4\pi -0.4}}{2} x=-\frac{\sqrt{4\pi -0.4}}{2}$$

Solve for x

$$x = \frac{\sqrt{4 \pi - 0.4}}{2} \approx 1.744016242$$

$$x = -\frac{\sqrt{4 \pi - 0.4}}{2} \approx -1.744016242$$