Solve pileft(x^2right)^2^+56+sqrt{z^4}*{y}^2=xy+{z}^x

$$\pi { \left( { x }^{ 2 } \right) }^{ { 2 }^{ } } +56+ \sqrt{ { z }^{ 4 } } \times { y }^{ 2 } =xy+ { z }^{ x }$$

Solve for y

$$\left\{\begin{matrix}y=\frac{\sqrt{x^{2}-4\pi z^{2}x^{4}-224z^{2}+4z^{x+2}}+x}{2z^{2}}\text{; }y=\frac{-\sqrt{x^{2}-4\pi z^{2}x^{4}-224z^{2}+4z^{x+2}}+x}{2z^{2}}\text{, }&x^{2}-4\pi z^{2}x^{4}-224z^{2}+4z^{x+2}\geq 0\text{ and }\left(Denominator(x)\text{bmod}2=1\text{ or }z>0\right)\text{ and }z\neq 0\\y=\frac{\pi x^{4}+56}{x}\text{, }&x>0\text{ and }z=0\end{matrix}\right.$$