Solve operatorname{iczb}a(1/(sqrt[3]{729+sqrt[4]{256}+2)^0})

$$\operatorname { iczb } a ( \frac { 1 } { ( \sqrt[ 3 ] { 729 } + \sqrt[ 4 ] { 256 } + 2 ) ^ { 0 } } )$$

Evaluate

$$iabcz$$

Solution Steps

Calculate \sqrt[3]{729} and get 9.

$$iczba\times \frac{1}{\left(9+\sqrt[4]{256}+2\right)^{0}}$$

Calculate \sqrt[4]{256} and get 4.

$$iczba\times \frac{1}{\left(9+4+2\right)^{0}}$$

Add 9 and 4 to get 13.

$$iczba\times \frac{1}{\left(13+2\right)^{0}}$$

Add 13 and 2 to get 15.

$$iczba\times \frac{1}{15^{0}}$$

Calculate 15 to the power of 0 and get 1.

$$iczba\times \frac{1}{1}$$

Anything divided by one gives itself.

$$iczba\times 1$$

Multiply i and 1 to get i.

$$iczba$$