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4\sqrt{2}-\log_{2}\left(2\right)\sqrt{2}
The base 2 logarithm of 16 is 4.
4\sqrt{2}-\sqrt{2}
The base 2 logarithm of 2 is 1.
3\sqrt{2}
Combine 4\sqrt{2} and -\sqrt{2} to get 3\sqrt{2}.