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-\frac{3}{2}+\log_{8}\left(\frac{1}{4}\right)
The base \frac{1}{4} logarithm of 8 is -\frac{3}{2}.
-\frac{3}{2}-\frac{2}{3}
The base 8 logarithm of \frac{1}{4} is -\frac{2}{3}.
-\frac{13}{6}
Subtract \frac{2}{3} from -\frac{3}{2} to get -\frac{13}{6}.