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x=\frac{8+1}{4}
Consider the second equation. Multiply 2 and 4 to get 8.
x=\frac{9}{4}
Add 8 and 1 to get 9.
y=2\times \left(\frac{9}{4}\right)^{2}-5\times \frac{9}{4}+3
Consider the first equation. Insert the known values of variables into the equation.
y=2\times \frac{81}{16}-5\times \frac{9}{4}+3
Calculate \frac{9}{4} to the power of 2 and get \frac{81}{16}.
y=\frac{81}{8}-5\times \frac{9}{4}+3
Multiply 2 and \frac{81}{16} to get \frac{81}{8}.
y=\frac{81}{8}-\frac{45}{4}+3
Multiply -5 and \frac{9}{4} to get -\frac{45}{4}.
y=-\frac{9}{8}+3
Subtract \frac{45}{4} from \frac{81}{8} to get -\frac{9}{8}.
y=\frac{15}{8}
Add -\frac{9}{8} and 3 to get \frac{15}{8}.
y=\frac{15}{8} x=\frac{9}{4}
The system is now solved.