Solve {c}{x+3=2}{4x+7y=13}

$$\left.\begin{array} { c } { x + 3 = 2 } \\ { 4 x + 7 y = 13 } \end{array} \right\}$$

Solve for x, y

$$x=-1$$

$$y = \frac{17}{7} = 2\frac{3}{7} \approx 2.428571429$$

Solution Steps

Consider the first equation. Subtract 3 from both sides.

$$x=2-3$$

Subtract 3 from 2 to get -1.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$4\left(-1\right)+7y=13$$

Multiply 4 and -1 to get -4.

$$-4+7y=13$$

Add 4 to both sides.

$$7y=13+4$$

Add 13 and 4 to get 17.

$$7y=17$$

Divide both sides by 7.

$$y=\frac{17}{7}$$

The system is now solved.

$$x=-1 y=\frac{17}{7}$$