Solve {r}{3s+5l=410}{+5*(s+26)=410}

$$\left. \begin{array} { r } { 3 s + 5 l = 410 } \\ { + 5 \cdot ( s + 26 ) = 410 } \end{array} \right.$$

Solve for s, l

$$s=56$$

$$l = \frac{242}{5} = 48\frac{2}{5} = 48.4$$

Solution Steps

Consider the second equation. Divide both sides by 5.

$$s+26=\frac{410}{5}$$

Divide 410 by 5 to get 82.

$$s+26=82$$

Subtract 26 from both sides.

$$s=82-26$$

Subtract 26 from 82 to get 56.

$$s=56$$

Consider the first equation. Insert the known values of variables into the equation.

$$3\times 56+5l=410$$

Multiply 3 and 56 to get 168.

$$168+5l=410$$

Subtract 168 from both sides.

$$5l=410-168$$

Subtract 168 from 410 to get 242.

$$5l=242$$

Divide both sides by 5.

$$l=\frac{242}{5}$$

The system is now solved.

$$s=56 l=\frac{242}{5}$$